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+[34]non-buffering stdin reading
+
+ [35]Ask Question
+ Asked 13 years, 1 month ago
+ Modified [36]9 years ago
+ Viewed 6k times
+ (BUTTON)
+ 9
+ (BUTTON) (BUTTON)
+
+ My test application is
+#include <sys/types.h>
+#include <sys/wait.h>
+#include <signal.h>
+#include <unistd.h>
+#include <stdio.h>
+#include <stdlib.h>
+#include <string.h>
+#include <fcntl.h>
+
+int main(int argc, char *argv[], char *envp[]) {
+ int fd[2];
+
+ if(pipe(fd) < 0) {
+ printf("Can\'t create pipe\n");
+ exit(-1);
+ }
+
+ pid_t fpid = fork();
+ if (fpid == 0) {
+ close(0);
+ close(fd[1]);
+ char *s = (char *) malloc(sizeof(char));
+ while(1) if (read(fd[0], s, 1)) printf("%i\n", *s);
+ }
+ close(fd[0]);
+ char *c = (char *) malloc(sizeof(char));
+ while (1) {
+ if (read(0, c, 1) > 0) write(fd[1], c, 1);
+ }
+ return 0;
+}
+
+ I want to see char-code after each entered char. But in fact *s is
+ printed only after '\n' in the console. So seems like stdin (file with
+ desc 0) is buffered. But the read function is buffer-less, isn't it?
+ Where am I wrong.
+
+ UPD: I use linux.
+
+ So the solution is
+#include <stdio.h>
+#include <stdlib.h>
+#include <unistd.h>
+#include <termios.h>
+
+int main(int argc, char *argv[], char *envp[]) {
+ int fd[2];
+
+ if(pipe(fd) < 0) {
+ printf("Can\'t create pipe\n");
+ exit(-1);
+ }
+
+ struct termios term, term_orig;
+
+ if(tcgetattr(0, &term_orig)) {
+ printf("tcgetattr failed\n");
+ exit(-1);
+ }
+
+ term = term_orig;
+
+ term.c_lflag &= ~ICANON;
+ term.c_lflag |= ECHO;
+ term.c_cc[VMIN] = 0;
+ term.c_cc[VTIME] = 0;
+
+ if (tcsetattr(0, TCSANOW, &term)) {
+ printf("tcsetattr failed\n");
+ exit(-1);
+ }
+
+ pid_t fpid = fork();
+ if (fpid == 0) {
+ close(0);
+ close(fd[1]);
+ char *s = (char *) malloc(sizeof(char));
+ while(1) if (read(fd[0], s, 1)) printf("%i\n", *s);
+ }
+ close(fd[0]);
+ char *c = (char *) malloc(sizeof(char));
+ while (1) {
+ if (read(0, c, 1) > 0) write(fd[1], c, 1);
+ }
+ return 0;
+}
+
+ * [37]c
+ * [38]linux
+ * [39]unix
+ * [40]posix
+
+ [41]Share
+ (BUTTON) Follow
+ [42]edited Dec 1, 2010 at 19:10
+ Ximik
+ asked Dec 1, 2010 at 18:54
+ Ximik's user avatar
+ [43]XimikXimik
+ 2,45533 gold badges2727 silver badges5353 bronze badges
+ 2
+ * 1
+ Note that this has nothing to do with buffering.
+ - [44]Simon Tóth
+ Dec 1, 2010 at 19:05
+ * Shouldn't the code reset the terminal attributes in the parent to
+ term_orig before exiting? You should probably also have the child
+ exit at some point -- it will continually get 0 from read() after
+ the parent shuts up shop. However, the parent is also in an
+ infinite loop; the processes only end when signalled. You really
+ need a signal handler that calls tcsetattr() with the original
+ terminal values for the main signals you're likely to get (that can
+ be handled): HUP, INT, QUIT perhaps, PIPE and TERM is a good set.
+ You can't do anything about KILL or STOP, of course.
+ - [45]Jonathan Leffler
+ Jan 19, 2021 at 3:27
+
+ [46]Add a comment |
+
+3 Answers 3
+
+ Sorted by: [47]Reset to default
+ [Highest score (default)___________]
+ (BUTTON)
+ 15
+ (BUTTON) (BUTTON)
+
+ Unfortunately, the behavior you're looking for is not possible with
+ standard ANSI C, and the default mode for UNIX terminal I/O is
+ line-oriented, which means you will always need an inputted \n
+ character to retrieve the input. You'll need to use terminal I/O
+ facilities that let you program in [48]non-canonical mode, so that each
+ key-press triggers an event. On Linux/UNIX, you can look into the
+ <termios.h> header, or the [49]ncurses library.
+ [50]Share
+ (BUTTON) Follow
+ [51]edited May 23, 2017 at 10:29
+ Community's user avatar
+ [52]CommunityBot
+ 111 silver badge
+ answered Dec 1, 2010 at 18:56
+ Charles Salvia's user avatar
+ [53]Charles SalviaCharles Salvia
+ 52.6k1414 gold badges130130 silver badges142142 bronze badges
+ 1
+ * 4
+ @Ximik, yes and they are not using standard ANSI C. Most use
+ external libraries such as ncurses or termcap.
+ - [54]Charles Salvia
+ Dec 1, 2010 at 18:59
+
+ [55]Add a comment |
+ (BUTTON)
+ 5
+ (BUTTON) (BUTTON)
+
+ It seems to me that your solution is a little bit complicated. Still
+ don't understand why do you need pipe and 2 process.
+#include <stdio.h>
+#include <stdlib.h>
+#include <unistd.h>
+#include <termios.h>
+
+int main(int argc, char *argv[], char *envp[]) {
+ struct termios term, term_orig;
+
+ if(tcgetattr(0, &term_orig)) {
+ printf("tcgetattr failed\n");
+ exit(-1);
+ }
+
+ term = term_orig;
+
+ term.c_lflag &= ~ICANON;
+ term.c_lflag |= ECHO;
+ term.c_cc[VMIN] = 0;
+ term.c_cc[VTIME] = 0;
+
+ if (tcsetattr(0, TCSANOW, &term)) {
+ printf("tcsetattr failed\n");
+ exit(-1);
+ }
+
+ char ch;
+ while (1) {
+ if (read(0, &ch, 1) > 0)
+ printf(" %d\n", ch);
+ }
+ return 0;
+}
+
+ [56]Share
+ (BUTTON) Follow
+ [57]edited Dec 30, 2014 at 12:56
+ answered Dec 30, 2014 at 12:14
+ Sam Toliman's user avatar
+ [58]Sam TolimanSam Toliman
+ 12311 silver badge55 bronze badges
+
+ [59]Add a comment |
+ (BUTTON)
+ 3
+ (BUTTON) (BUTTON)
+
+ Unix buffers your tty characters inside the kernel in part so that
+ programs don't have to individually handle line editing unless they
+ want to.
+
+ You can instruct the tty driver to give you the bytes immediately.
+ There are various libraries that make this a bit easier than using the
+ raw ioctl. You might start with termios(3).
+ [60]Share
+ (BUTTON) Follow
+ answered Dec 1, 2010 at 18:59
+ DigitalRoss's user avatar
+ [61]DigitalRossDigitalRoss
+ 144k2525 gold badges250250 silver badges330330 bronze badges
+ 1
+ * 3
+ And sadly nobody got around to improving this kernel-level line
+ editing to make it actually usable... In principle it could be
+ nearly as nice as readline.
+ - [62]R.. GitHub STOP HELPING ICE
+ Dec 1, 2010 at 20:46
+
+ [63]Add a comment |
+
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